Jump to content

Search the Community

Showing results for tags 'fdmemtable'.

More search options

  • Search By Tags

    Type tags separated by commas.
  • Search By Author

Content Type


  • Delphi Questions and Answers
    • Algorithms, Data Structures and Class Design
    • VCL
    • FMX
    • RTL and Delphi Object Pascal
    • Databases
    • Network, Cloud and Web
    • Windows API
    • Cross-platform
    • Delphi IDE and APIs
    • General Help
    • Delphi Third-Party
  • C++Builder Questions and Answers
    • General Help
  • General Discussions
    • Embarcadero Lounge
    • Tips / Blogs / Tutorials / Videos
    • Job Opportunities / Coder for Hire
    • I made this
  • Software Development
    • Project Planning and -Management
    • Software Testing and Quality Assurance
  • Community
    • Community Management

Find results in...

Find results that contain...

Date Created

  • Start


Last Updated

  • Start


Filter by number of...


  • Start




Found 2 results

  1. hi, did anybody have this issue: 1) FDquery1 to some MSSQL table 2) view dataset of FDquery1 thru DBGrid - 3 distinct records (same result in SSMS) 3) FDMemTable1.CopyDataSet(FDquery1,[coStructure, coRestart, coAppend]) 4) view dataset of FDMemTable1 thru DBGrid - 9 records (3 original records copied 3 times) what could be a problem?
  2. Roger Cigol

    Primary Key on FDMemTable

    I am using DUnit based unit tests to devlop FireDAC VCL C++ code (Sydney 10.4.1). I am using FDMemTables to create test instances of database tables to unit test FDQuery operations etc. So I want the FDMemTable to accurately reflect the structure of the eventual end database table(s). Some (most) of these tables need a primary key, often consisting of several fields. I can find how to add indexes to FDMemTables { using TFDIndex *NewIndex = MyFDMemTable->Indexes->Add() } but I can't find a way to add a primary key to the FDMemTable. Question ; can anyone show me C++ code (or Delphi code is fine too) how to add a primary key to a newly created FDMemTable.