Ord Funcition

[Henry Olive 5]

Good Day

 

I'm trying to get a char's alphabetic order number

for example  A=1,  C=3... etc.

 

Edit2.Text := IntToStr(Ord(Edit1.Text));

with above code I'm getting  37331868 for A (expecting 1)

what am i doing wrong ?

 

Thank You

[Uwe Raabe 2061]

Edit1.Text is a string, which internally is a pointer. So Ord returns the value of the pointer.

 

Better identify the char you are interested in: Ord(Edit1.Text[1]);

[Henry Olive 5]

Thank you so much Uwe, your code works but the result is not as my expectation

 

//Edit1.Text = A

Edit2.Text := IntToStr(Ord(Edit1.Text[1]));    Result = 65,  Expecting 1

 

//Edit1.Text = B

Edit2.Text := IntToStr(Ord(Edit1.Text[1]));    Result = 66,  Expecting 2

 

 

 

 

[Kas Ob. 121]

7 minutes ago, Henry Olive said:

//Edit1.Text = A

Edit2.Text := IntToStr(Ord(Edit1.Text[1]));    Result = 65,  Expecting 1

 

//Edit1.Text = B

Edit2.Text := IntToStr(Ord(Edit1.Text[1]));    Result = 66,  Expecting 2

If you have capital Latin letters then just subtract 64.

In case of small Latin letters then subtract 96.

 

https://en.wikipedia.org/wiki/ASCII

[Uwe Raabe 2061]

Ord returns the ordinal value of the character, not its position in the alphabet.

[Henry Olive 5]

Thank you so much Kas, Uwe

My problem solved.