houssam1984 0 Posted February 24 hello brothers , i am trying to make an android app useing delphi 11.3 , the app should read storage where i can select a pdf file the upload it into a distant server -getting permission is ok - i asked chatgpt and it gave me a model where the file path is shown in an edit "supposly" , when i run it , it show files but when i select a file nothing happened " i dont get anything in my edit" - then when i tr wrote the path of the file to upload "MANUALY" the idhttp send can not open file permission denied -please can any one help me !!! Share this post Link to post
Sherlock 663 Posted February 24 What protocols does this distant server support? Which authentication steps need to be taken? Can you manually or by other means do this task? As soon as you can answer these questions...you'll get an educated answer. 1 Share this post Link to post
houssam1984 0 Posted February 24 thank you , its a simple server with http protocol , what i wanted is choose pdf file on an android device click a button "Upload" and the file will be uploaded to the server over http , i am sorry if i couldnt explain my self well Share this post Link to post
#ifdef 12 Posted February 24 (edited) https://www.youtube.com/watch?v=ouNEdebsq8Y + https://github.com/dondonondon/FMXTutorialYoutube/tree/main/Sesi%201/%23012%20Upload%20%26%20Download%20WebService%20.%20RESTAPI%20%26%20Permission Edited February 24 by #ifdef Share this post Link to post
Remy Lebeau 1390 Posted February 24 8 hours ago, houssam1984 said: - getting permission is ok - idhttp send can not open file permission denied That's a contradiction. Either you have the permissions or you don't. What does your code look like that is asking the user for permission to access the file, and the code that tries to upload the file? Share this post Link to post
houssam1984 0 Posted February 24 42 minutes ago, Remy Lebeau said: That's a contradiction. Either you have the permissions or you don't. What does your code look like that is asking the user for permission to access the file, and the code that tries to upload the file? hello ; permissions are to read storage in my android device ; if you dont get permission to read storage you cant access file location var Intent: JIntent; const PermissionReadExStrg = 'android.permission.READ_EXTERNAL_STORAGE'; begin if not PermissionsService.IsPermissionGranted(JStringToString(TJManifest_permission.JavaClass.READ_EXTERNAL_STORAGE)) then begin PermissionsService.RequestPermissions([PermissionReadExStrg], procedure(const APermissions: TClassicStringDynArray; const AGrantResults: TClassicPermissionStatusDynArray) begin if (Length(AGrantResults) = 1) and (AGrantResults[0] = TPermissionStatus.Granted) then { activate or deactivate the location sensor } ShowFileChooser else begin ShowMessage('permission not granted'); end; end); end else ShowFileChooser; end; than showfilechooser procedure looks like : var Intent: JIntent; m:TMessageResultNotification; begin Intent := TJIntent.Create; Intent.setAction(TJIntent.JavaClass.ACTION_GET_CONTENT); Intent.setType(StringToJString('application/pdf')); SharedActivity.startActivityForResult(Intent, 0); end; and the uploading procedure looks like var HTTP: TIdHTTP; FormData: TIdMultiPartFormDataStream; begin if Edit1.Text = '' then begin ShowMessage('Please select a file.'); Exit; end else begin HTTP := TIdHTTP.Create(self); FormData := TIdMultiPartFormDataStream.Create; try FormData.AddFile('file', Edit1.Text, 'application/pdf'); HTTP.Post('my HTTP server', FormData); ShowMessage('File uploaded successfully.'); except on E: Exception do ShowMessage('Error uploading file: ' + E.Message); end; FormData.Free; HTTP.Free; end; the app runs normally but when i choose the file and click UPLOAD Button Nothing Happens Share this post Link to post
houssam1984 0 Posted February 24 4 hours ago, #ifdef said: https://www.youtube.com/watch?v=ouNEdebsq8Y + https://github.com/dondonondon/FMXTutorialYoutube/tree/main/Sesi%201/%23012%20Upload%20%26%20Download%20WebService%20.%20RESTAPI%20%26%20Permission well the video is great but what i want is to choose a file on my device from sdcard for exemple than upload it to a server over HTTP or REST Share this post Link to post
Remy Lebeau 1390 Posted February 24 (edited) You did not show the code that receives the file path from the file chooser and puts it into the TEdit, or show what the file path actually looks like. But ACTION_GET_CONTENT is documented as returning a "content:" uri, which requires you to use the ContentResolver class to access the file data. But TIdMultipartFormDataStream.AddFile() uses TFileStream, which wants direct access to the file, which will not work with a "content:" uri on modern Android versions. So you will likely have to either: access the file yourself via Android APIs and read its byte data into a TMemoryStream or TByteStream, or create a custom TStream that wraps an Android InputStream from the ContentResolver.openInputStream() method And then use TIdMultipartFormDataStream.AddFormField() instead of TIdMultipartFormDataStream.AddFile() to send whichever TStream you end up using. Alternatively, you can use ContentResolver to extract the underlying "file:" uri from a "content:" uri, and then you should be able to open the file using a normal TFileStream (provided you have permissions to the file). Also, when using ACTION_GET_CONTENT, the ACTION_GET_CONTENT documentation says to wrap your Intent with Intent.createChooser(), and also include CATEGORY_OPENABLE and FLAG_GRANT_READ_URI_PERMISSION on your Intent. Edited February 25 by Remy Lebeau 3 Share this post Link to post
houssam1984 0 Posted February 25 4 hours ago, Remy Lebeau said: You did not show the code that receives the file path from the file chooser and puts it into the TEdit, or show what the file path actually looks like. But ACTION_GET_CONTENT is documented as returning a "content:" uri, which requires you to use the ContentResolver class to access the file data. But TIdMultipartFormDataStream.AddFile() uses TFileStream, which wants direct access to the file, which will not work with a "content:" uri on modern Android versions. So you will likely have to either: access the file yourself via Android APIs and read its byte data into a TMemoryStream or TByteStream, or create a custom TStream that wraps an Android InputStream from the ContentResolver.openInputStream() method And then use TIdMultipartFormDataStream.AddFormField() instead of TIdMultipartFormDataStream.AddFile() to send whichever TStream you end up using. Alternatively, you can use ContentResolver to extract the underlying "file:" uri from a "content:" uri, and then you should be able to open the file using a normal TFileStream (provided you have permissions to the file). Also, when using ACTION_GET_CONTENT, the ACTION_GET_CONTENT documentation says to wrap your Intent with Intent.createChooser(), and also include CATEGORY_OPENABLE and FLAG_GRANT_READ_URI_PERMISSION on your Intent. ups !! i didnt say i am beginner , i partally understand what you said but if it is not toooooooooo far from me can you provide me any examples of code??? Share this post Link to post
houssam1984 0 Posted February 25 THANK YOU SO MUCH FOR ANSWERING MY STUPIDITIES Share this post Link to post
Remy Lebeau 1390 Posted February 26 20 hours ago, houssam1984 said: ups !! i didnt say i am beginner , i partally understand what you said but if it is not toooooooooo far from me can you provide me any examples of code??? Sorry, I don't have any examples to give you, as I don't write code for Android. 1 Share this post Link to post